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1. Find the zeros of the polynomial function \[ f(x)=x^{4}-2 x^{3}+4 x^{2}-8 x ...
May 20, 2024
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Solution by Steps
step 1
To find the zeros of the polynomial function
f
(
x
)
=
x
4
−
2
x
3
+
4
x
2
−
8
x
f(x) = x^4 - 2x^3 + 4x^2 - 8x
f
(
x
)
=
x
4
−
2
x
3
+
4
x
2
−
8
x
, we start by factoring out the common term
x
x
x
step 2
Factor out
x
x
x
from the polynomial:
x
(
x
3
−
2
x
2
+
4
x
−
8
)
=
0
x(x^3 - 2x^2 + 4x - 8) = 0
x
(
x
3
−
2
x
2
+
4
x
−
8
)
=
0
step 3
Set each factor equal to zero:
x
=
0
x = 0
x
=
0
and
x
3
−
2
x
2
+
4
x
−
8
=
0
x^3 - 2x^2 + 4x - 8 = 0
x
3
−
2
x
2
+
4
x
−
8
=
0
step 4
Solve the cubic equation
x
3
−
2
x
2
+
4
x
−
8
=
0
x^3 - 2x^2 + 4x - 8 = 0
x
3
−
2
x
2
+
4
x
−
8
=
0
. This can be done by finding the roots of the cubic polynomial
step 5
Using the Asksia-LL calculator result, the roots of the cubic polynomial
x
3
−
2
x
2
+
4
x
−
8
=
0
x^3 - 2x^2 + 4x - 8 = 0
x
3
−
2
x
2
+
4
x
−
8
=
0
are
x
=
2
x = 2
x
=
2
and
x
=
±
2
i
x = \pm 2i
x
=
±
2
i
step 6
Combine all the roots:
x
=
0
x = 0
x
=
0
,
x
=
2
x = 2
x
=
2
, and
x
=
±
2
i
x = \pm 2i
x
=
±
2
i
Answer
The zeros of the polynomial function
f
(
x
)
=
x
4
−
2
x
3
+
4
x
2
−
8
x
f(x) = x^4 - 2x^3 + 4x^2 - 8x
f
(
x
)
=
x
4
−
2
x
3
+
4
x
2
−
8
x
are
x
=
0
x = 0
x
=
0
,
x
=
2
x = 2
x
=
2
, and
x
=
±
2
i
x = \pm 2i
x
=
±
2
i
.
Key Concept
Finding the zeros of a polynomial function
Explanation
To find the zeros of a polynomial function, factor the polynomial and solve for the values of
x
x
x
that make each factor equal to zero.
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