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1. A single qubit is prepared in the state \[ |\psi\rangle=\frac{3}{5}|+\rangle...
Sep 28, 2024
Solution by Steps
step 1
For question 1(a), the possible outcomes in the computational basis are 0 |0\rangle and 1 |1\rangle . The probabilities are calculated as follows: P(0)=0ψ2 P(0) = |\langle 0 | \psi \rangle|^2 and P(1)=1ψ2 P(1) = |\langle 1 | \psi \rangle|^2
step 2
The state ψ=35+4i5 |\psi\rangle = \frac{3}{5}|+\rangle - \frac{4i}{5}|-\rangle can be expressed in the computational basis as ψ=3512(0+1)4i512(01) |\psi\rangle = \frac{3}{5}\frac{1}{\sqrt{2}}(|0\rangle + |1\rangle) - \frac{4i}{5}\frac{1}{\sqrt{2}}(|0\rangle - |1\rangle)
step 3
Simplifying this gives ψ=(3524i52)0+(352+4i52)1 |\psi\rangle = \left(\frac{3}{5\sqrt{2}} - \frac{4i}{5\sqrt{2}}\right)|0\rangle + \left(\frac{3}{5\sqrt{2}} + \frac{4i}{5\sqrt{2}}\right)|1\rangle
step 4
The probabilities are then calculated as P(0)=34i522 P(0) = \left|\frac{3 - 4i}{5\sqrt{2}}\right|^2 and P(1)=3+4i522 P(1) = \left|\frac{3 + 4i}{5\sqrt{2}}\right|^2
step 5
For question 2, the probability of measuring the qubit in state 1 |1\rangle is given by P(1)=322=34 P(1) = \left|\frac{\sqrt{3}}{2}\right|^2 = \frac{3}{4}
step 6
For question 3, we verify that P0+P1=E P_0 + P_1 = E by showing that the projection operators P0=00 P_0 = |0\rangle\langle 0| and P1=11 P_1 = |1\rangle\langle 1| sum to the identity matrix E=00+11 E = |0\rangle\langle 0| + |1\rangle\langle 1|
step 7
For question 4(a), applying the Hadamard gate H H to the first qubit of 01 |01\rangle results in H0=12(0+1) H|0\rangle = \frac{1}{\sqrt{2}}(|0\rangle + |1\rangle) , giving the state 12(0+1)1 \frac{1}{\sqrt{2}}(|0\rangle + |1\rangle)|1\rangle
step 8
For question 4(b), applying the Hadamard gate H H to the second qubit results in 0H1=012(01) |0\rangle H|1\rangle = |0\rangle \frac{1}{\sqrt{2}}(|0\rangle - |1\rangle) , giving the state 012(01) |0\rangle \frac{1}{\sqrt{2}}(|0\rangle - |1\rangle)
[1] Answer
C
[2] Answer
C
[3] Answer
A
[4] Answer
A
Key Concept
Quantum Measurement and Probability
Explanation
The probabilities of measuring a qubit in a specific state are derived from the squared magnitudes of the coefficients in its state representation. The Hadamard gate transforms qubit states, affecting measurement outcomes.
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